for two concentric circle of radius 25cm and 7cm the chord of the larger circle touches smaller . find its length
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Answer:
hy
Step-by-step explanation:
given,
Two concentric circles with radii 7cm and 25cm .
to find,
the length of the cord of the larger circle which touches the smaller circle.
on applying Pythagoras theorem in triangle AOC
(AO) ^2 = (AC) ^2+(OC) ^2
(25) ^2 = (AC) ^2+(7) ^2
625 = (AC) ^2+49
(AC) ^2 = 625-49
AC = √576
AC = 24
Similarly, if we apply Pythagoras theorem in triangle OCB,
we get CB=24cm
therefore, AB = AC+CB
AB = 24+24
AB = 48cm
hence, the length of the cord of the larger circle which touches the smaller circle is 48cm
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