For two concentric circles of radius 25 cms and 7cms the cord of the larger circle
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Answers
Answered by
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Step-by-step explanation:
REF.Image
AB=?
In ΔOAC-
OA2 =α 2+AC 2
25 2=7 2+AC 2
AC 2 =625−49=576
AC=24
Similarly
In ΔOCB-
OB 2=OC 2+BC 2
25 2=7 2 +BC 2
BC 2=625−49
BC=24
AB=AC+CB
AB=48cm
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