Question

For two events A and B, P (B) = 0.3, P (A but not B) = 0.4 and P (not A) = 0.6. The events

A and B are

(a) exhaustive (b) independent

(c) equally likely (d) mutually exclusive​

Answer 1

Answer:

mutually exclusive

Step-by-step explanation:

p(A')=0.6==>1-p(A)=0.6(given)--1

              ==>p(A)=0.4

p(A)-p(AintersectionB)=0.4(given)--2

from 1 and 2p(AintersectionB)=0

hence mutually exclusive

Answer 2

Option D) For two events A and B, P (B) = $0.3$, P (A but not B) = $0.4$ and P (not A) = $0.6$. The events are mutually exclusive.

Step-by-step explanation:

P(B) = $0.3$

P(A ∩ B')= $0.4$

$P(A')=$ $0.6$

$1- P(A)=0.6\\P(A)=0.4$

P(A)+P(B)=$0.7$

$0.7\neq 1$

This means A and B are not Exhaustive.

We get P(A ∩ B) =$0$

This means, A ∩ B =∅
Mutually exclusive events.

option d)