Question

For two forces p and Q acting at a point maximum resultant is 300 N and minimum magnitude is 800 N find the value of p and Q​

Answer 1

GIVEN :-

Two force P and Q .

Maximum resultant = 300.

Minimum resultant = 800 N.

TO FIND :-

The value of P and Q.

SOLUTION :-

The maximum resultant force can be written as,

$\implies \sf \: P + Q = 300....(1)$

The minimum resultant force can be written as,

$\implies \sf \: P - Q = 800....(2)$

From equation 1 we have,

$\implies \sf \: P = 300 - Q ....(3)$

From equation 2 we have,

$\implies \sf \: P = 800 + Q ....(4)$

On comparing equation 3 and 4 we get,

$\implies \sf \: 300 - Q = 800 + Q$

$\implies \sf \: - 2Q = 500$

$\implies \sf \: - Q = \dfrac{500}{2}$

$\implies \sf \: Q = - 250$

Now substitute the value of Q in equation 1,

$\implies \sf \: P - 250 = 300$

$\implies \sf \: P= 300 + 250$

$\implies \sf \: P=550$

Hence the value of P is 550 and value of Q is -250.

$\huge \sf {\orange {\underline {\pink{\underline {Hope \: It \: Helps \: Uhh♥}}}}}$

Answer 2

GIVEN :-

Two force P and Q .

Maximum resultant = 300.

Minimum resultant = 800 N.

TO FIND :-

The value of P and Q.

SOLUTION :-

The maximum resultant force can be written as,

$\implies \sf \: P + Q = 300....(1)$

The minimum resultant force can be written as,

$\implies \sf \: P - Q = 800....(2)$

From equation 1 we have,

$\implies \sf \: P = 300 - Q ....(3)$

From equation 2 we have,

$\implies \sf \: P = 800 + Q ....(4)$

On comparing equation 3 and 4 we get,

$\implies \sf \: 300 - Q = 800 + Q$

$\implies \sf \: - 2Q = 500$

$\implies \sf \: - Q = \dfrac{500}{2}$

$\implies \sf \: Q = - 250$

Now substitute the value of Q in equation 1,

$\implies \sf \: P - 250 = 300$

$\implies \sf \: P= 300 + 250$

$\implies \sf \: P=550$

Hence the value of P is 550 and value of Q is -250.

$\huge \sf {\orange {\underline {\pink{\underline {Hope \: It \: Helps \: Uhh♥}}}}}$