Question

For two independent events A and B for which P(A) = 1/2 and P(B) = 1/3. Find the probability that one of them occur.

Answer 1

A and B are independent event

thus P(A∩B) = P(A)*P(B)

now to find the probability that one of them occur
i.e.

P(AUB) = P(A)+P(B) -P(A∩B)


= (1/2)+(1/3)-(1/2)(1/3)



=(5/6)-(1/6)


= 4/6




= 2/3