Question

For two resistors R, and R2, connected in
parallel, the relative error in their equivalent
resistance is (Where R4 = (10.0 + 0.1), and
R2 = (20.0 0.4) 2)
[NCERT Pg. 27]
(1) 0.08
(2) 0.05
(3) 0.01
(4) 0.04
4​

Answer 1

Answer:

0.08

Explanation:

first of all find the equivalent resistance by the formula;

1/Req = 1/R1 + 1/R2

Req = R1.R2/R1+ R2

=20.10/20+10

Req=6.66....

Now, parellal connection error..

R1²(dB) +R2²(dA)

_______________

(R1+R2) ²

=0.08 is the required answer...