Question

for two resistors R1 and R2 connected in parallel, find the relaive error in their equilavent resistor .if R1=(50+/-2)ohm and R2=(100+/-3)​

Answer 1

Hope it helps

There can be a calculation mistake

But the approach is correct

Req =33.3ohm

Delta Req /Req = Delta R1 / R1^2 + R2/R2^2

Substitute the values and you will get 11/9 as relative error

Hope it helps

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