Question

For two resistors R1, and R2, connected in parallel, the relative error in their equivalent resistance is (Where R1 = (10.0 +- 0.1)ohm and R 2= (20.0 +-0.4)ohm) (1) 0.08 (2) 0.05 (3) 0.01 (4) 0.04 kindly define step by step and clear to ans pls..

Answer 1

Answer:

Two resistors, R

1

andR

2

are connected in parallel.

We know,

R

e

1

=

R

1

1

+

R

2

1

Then R

e

=

R

1

+R

2

R

1

R

2

=

50+100

50×100

=

150

5000

=

3

100

Now, Parallel Connection error:

=

(R

1

+R

2

)

2

R

1

2

(dB)+R

2

2

(dA)

=

150

2

50

2

(3)+100

2

(2)

=

150×150

7500+20000

=

9

11

Relative Error =

(100/3)

(11/9)

=0.03666