for two vectors A and B if A+B=C and A+B=C , then prove that vector A and B are perpendicular to each other
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We have,
a+b=ca+b=c ……………………(1)
Also,
|a|+|b|=|c|…………(2)
Square the equation, (1), we get,
(a+b).(a+b)=c.c
Implies,
|a|2+|b|2|+2(a.b)=|c| ……….(3)
From (2), we can get,
|a|2+|b|2|+2|a||b|=|c|2 ………(4)
Since the RHS’s of (3) and (4) are same, we can equate them, we get,
|a|2+|b|2|+2(a.b)=|a|2+|b|2|+2|a||b|
Implies,
a.b=|a||b|
Dot Product of 2 vectors is the product of absolute values of the vectors with the cosine of angle between them. So,
|a||b|cosx=|a||b|
Here, xx is the angle between aa and bb.
So,
cosx=1
Take cosine inverse or arccosarccos on both sides, we get,
x=cos−1(1)
Implies,
x=0
So, the angle between the 2 given vectors is 0, which means they’re parallel.
I hope my answer was helpful.
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