Question

For v2x2 – 5x + V2 = 0, the value of discriminate is - PLS HELP.. DON'T SPAM ​

Answer 1

Correct Question:

For √2x² - 5x + √2, the value of discriminant is

Answer:

17

Step-by-step explanation:

The given equation is √2x² - 5x + √2 which is in the form of ax² + bx + c, where value of a is √2, b is -5 and c is +√2.

We need to find out the value of discriminant i.e. D.

Formula for finding the value of discriminant is D = b² - 4ac

Substitute value of a = √2, b = -5 and c = √2 in D = b² - 4ac to get the value of D.

→ D = (-5)² - 4(√2)(√2)

We know that-

• Product of (-) and (-) is (+)
• Product of (+) and (+) is (+)
• Product of (-) and (+) is (-)
• Product of (+) and (-) is (-)

Therefore,

→ D = 25 - 4(√2)²

→ D = 25 - 4(2)

→ D = 25 - 8

→ D = 17

Hence, the value of discriminant is 17.

Answer 2

Answer:

17

Step-by-step explanation:

√2x² - 5x + √2 = 0

here,

a = √2

b = -5

c = √2

so, by using Discriminat Formula.

Discriminat (D) = b² - 4ac

⇒ (-5)² - 4(√2)(√2)

⇒ 25 - 4(2)

⇒ 25 - 8

⇒ 17