Question

for wat value of k will k+9,2k-1,2k+7 are the consecutive terms of an AP

Answer 1

Answer :

Since, (k + 9), (2k - 1) and (2k + 7) are the consecutive terms of an AP,

(2k - 1) - (k + 9) = (2k + 7) - (2k - 1)

⇒ 2k - 1 - k - 9 = 2k + 7 - 2k + 1

⇒ (2 - 1)k + (- 1 - 9) = (2 - 2)k + (7 + 1)

⇒ k - 8 = 8

⇒ k = 8 + 8

⇒ k = 16

∴ the value of k is 16.

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Answer 2

let d = common difference
than k= 14
solution shown in photo