Physics, asked by janvibh2085, 1 year ago

For what angel of projection the range of projectile equals the maximum height

Answers

Answered by aayushmandloi484
2

Explanation:

Range = u²sin(2θ)/g

Hmax=usinθ/g

=> u²sin(2θ) = usin(θ)

g g

=> 2sin(θ)cos(θ) = sin(θ)

=> sinθ(2cosθ-1)=0

=> sinθ = 0 or cosθ =1/2

=> θ=0 or θ=60°

since angle of projection can't be 0° hence 60° is the required answer....

please mark as brainliest if this helps to you....

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