Question

for what angle of incidence the angle of deviation will be minimum for the refraction of light from rarer medium to denser medium​

Answer 1

Answer:

Given: A ray of light travels from an optically denser to rarer medium. The critical angle for the two media is C.

To find the maximum possible deviation of the ray

Solution:

Critical angle is the angle of incidence for which the angle of refraction is

2

π

for a given pair of media.

Let θ be the angle of incidence and ϕ the angle of refraction.

When the ray passes from denser to rarer medium, the deviation is δ=ϕ−θ. If θ=C then ϕ=

2

π

and deviation δ=

2

π

−C. This is the maximum deviation. When total internal reflection occurs, the deviation is given by δ=π−2θ. Here δ is maximum when θ is minimum. The minimum value of θ is C.

Hence maximum deviation δ=π−2C.

Answer 2

Answer:

A ray of light is moving from a rarer medium to a denser medium and strikes a plane mirror placed at 90

o

to the direction of the ray as shown in the diagram.

(i) Copy the diagram and mark arrows to show the path of the ray of light after it is reflected from the mirror.

(ii) Name the principle you have used to mark the arrow to show the direction of the ray.

Explanation:

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