Question

For what concentration of ag+ will the emf of the cell be 0.422v at 25degree c if the concentration of cu2+ is 0.1m

Answer 1

Hey dear,

● Answer -
Ag+ = 0.07 M

● Explaination -
In the given cell, silver acts as cathode and copper as anode.

Half cell reactions include -
Anode : Cu --> Cu2+ + 2e-
Cathode : Ag+ + e- --> Ag
Net cell reaction is -
Cu + 2Ag+ --> Cu2+ + 2Ag

Thus,
E°cell = Ered - Eox
E°cell = 0.80 - 0.34
E°cell = 0.46 V

EMF of cell is calculated by -
Ecell = E°cell - 0.0592/n log[(Cu2+)/(Ag+)^2]
0.422 = 0.46 - log[0.1/(Ag+)^2]

Solving for Ag+,
Ag+ = 0.07 M

Hope this helps you...