for what had value ofp (4) Is a zero in
the polynomial x ² - 2x - (7p+3)
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Answered by
1
Answer:
p(4) = x^2 - 2x - (7p+3)
=4^2-2×4-7p-3
=16-8-3-7p
=16-11-7p
=5-7p
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Answered by
1
f(x)= x²-2x -(7p+3)
f(4) = 4²-2(4)-7p-3
4 is a zero of the given polynomial, therefore
4²-2(4)-7p-3=0
16-8-7p-3=0
-7p+5=0
-7p= -5
p= 5/7
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