Question

For what least value of n a natural number (24)^n is divider by 8

Answer 1

Answer:

The value of n is 1.

Step-by-step explanation:

First, we will check if 24 is divisible by 8 or not.

So, we get

24 = 8*3 + 0 (Euclid's algorithm)

Since, the remainder is 0 , therefore 24 is completely divisible by 8.

Then, we will check for the required value of n by hit and trial method.

Putting n = 1,

$({24})^{1}$

i.e.

24 itself.

We have seen it before that 24 is divisible by 8.

Therefore, the required value of n is 1.

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