for what m is x^3-2mx^2+16 is divisible by x+2
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Answered by
177
Answer:
m = 1
Explanation:
Let p(x) = x³-2mx²+16
It is given that, p(x) is divisible by (x+2) .
By factor theorem ,
(x+2) is a factor of p(x).
Therefore,
p(-2) = 0
=> (-2)³-2m(-2)²+16 = 0
=> -8 -2m × 4 + 16 = 0
=> -8 -8m+16 = 0
=> -8m+8 = 0
=> -8m = -8
=> m = (-8)/(-8)
=> m = 1
Therefore,
m = 1
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