For what of k the given system of linear equation has unique solution .
2x+3y = 5, x - 5y =k
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2x+3y=5, x-5y=k.
2x+3y-5=0, x-5y-k=0.
a1/a2=2/1=2.
b1/b2=3/-5.
c1/c2=-5/-k=5/k.
a1/a2 is not equal to b1/b2 is not equal to c1/c2.
2/1=5/k.
2×k=1×5.
2k=5.
k=5/2.
So, there is a unique solution.
I think this is your answer.
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