Question

For what possible value of b the following numbers are divisible by 3 ?
(ii) 83b49
(i) 7b23​

Answer 1

Answer:

The values of b can be 0, 3, 6 and 9

Step-by-step explanation:

Divisibility rule of 3:

Sum of all digits will add up to a multiple of 3

So, in this way

a) 8+3+b+4+9 =multiple of 3

24 +b=multiple of 3

b) 7+b+2+3 =multiple of 3

12+b=multiple of 3

By putting the values of 0,3,6,9 we will get multiple of 3