Question

for what the value of K, the
points (K,-2), (1,4) and (-3,16)
in given order are collinear?​

Answer 1

sorry for poor quality

Answer 2

The value of k is 3.

Step-by-step explanation:

Given : The points (K,-2), (1,4) and (-3,16)  in given order are collinear.

To find : For what the value of K?

Solution :  

When three points are collinear then the condition is  

$x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) = 0$

Where, $x_1 = K, x_2 = 1,x_3 = -3, y_1 =-2, y_2 =4, , y_3 =16$

Substituting the values,

$K(4-16) + 1(16-(-2)) + (-3)(-2-4) = 0$

$-12k +18+18= 0$

$-12k + 36= 0$

$12k=36$

$k=\frac{36}{12}$

$k=3$

Therefore, The value of k is 3.

#Learn more

Write the value of k, if points (7,-2), (5,1),(3,k) are coolinear

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