Question

for what the value of k, the roots of the equation x²+4k+k=0 are real?​

Answer 1

Answer:

x2 – 4kx + k = 0 It’s of the form of ax2 + bx + c = 0 Where, a =1, b = -4k, c = k For the given quadratic equation to have real roots D = b2 – 4ac ≥ 0 D = (-4k)2 – 4(1)(k) ≥ 0 ⇒ 16k2 – 4k ≥ 0 ⇒ 4k(4k – 1) ≥ 0 ⇒ k ≥ 0 and k ≥ 1414 ⇒ k ≥ 1414 The value of k should be greater than or equal to 1414to have real roots

Answer 2

Answer:

let X= 2

(2)^+4k+K=0

4+4k+K=0

4k+K=4

4k=4

K=1