For what the value of m,is the polynomial x^3 -2mx^2+16 divisible by (x+2)
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Answer:
Let g(x) be x+2 and p(x) be x³ - 2mx² + 16
g(x) = 0
x+2 =0
x=-2
Putting the value of x in p(x)
p(-2) = (-2)³ -2m(-2)² +16=0
= -8 -8m +16 = 0
= 8-8m = 0
= -8m =0-8
= -8m =-8
= m =-8/-8
= m = 1
Hence, the value of m is 1
Hope it helps you!
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0
Soln:-
m = 3/2
refer to the attachment
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