Question

for what valu of k does kx2 - 6x-1 =0 have no real root
​

Answer 1

Step-by-step explanation:

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Class 10

>>Maths

>>Quadratic Equations

>>Nature of Roots

>>For what value of k the equation kx^2 +

Question

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For what value of k the equation kx

2

+6x+1=0 has equal roots?

Medium

Solution

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Correct option is A)

This is the form ax

2

+bx+c=0

Here a=k,b=6,c=1

Δ=b

2

−4ac

Since the roots are equal, discriminant=b

2

−4ac=0.

Therefore, (6)

2

−4×k×1=0

⇒36−4k=0

⇒4k=36

⇒ k=

4

36

=9

⇒ k=9