Question

for what value 'b' the quadratic polynomial ax^2+bx+c has zeroes equal to the magnitude but opposite in sign

Answer 1

Answer:

Step-by-step explanation:

Let p(x) be ax^2 + bx + c

Since zeroes are equal in magnitude and opposite in sign

Let M and -M be the zeroes of p(x)

Sum of zeroes = -(Coefficient of x)

/Coefficient of x^2

M+(-M) = -b/a

M-M = -b/a

0 = -b/a

-b = 0

b = 0