For what value if "k" will the consecutive terms :
2k + 1,
3k + 3
&
5k - 1.
form an AP
If u knows then only answer it....!!!!
If not then pls don't waste
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Answered by
2
Answer:
your answer is here nandu....
AP-. 2k+1 , 3k+3 , 5k-1..........
we know that,
a2-a1= d ; &. a2-a1=d
then,
3k+3-(2k+1) = 5k-1 - (3k+3)
3k+3-2k-1= 5k-1-3k-3
1k+2= 2k-4
2+4= 2k-1k
6=k
k=6"
to check,
if we apply value of k in AP, we get,
13,21,29........
wkt,.
21-13 = 29-21
then, 8= 8"
hope this will help you nandu....
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Answered by
1
sorry I don't know the answer
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