for what value K the points A(1,5), B(K,1) and C (4,11) are collinear
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for the points to be collinear,
x1(y2-y3) + x2(y3-y1) + x3(y1-y2)=0... (1)
now the points are A(1,5) B(K,1) and C(4,11) i.e.
x1=1 y1=5
x2=K y2=1
x3=4 y3=11
put these values in equation 1..
1(1-11) + K(11-5) + 4(5-1) =0
-10+ 6K +16 =0
6K+6=0.... 6K=-6
i.e. K=-1...
hope it helps you..
x1(y2-y3) + x2(y3-y1) + x3(y1-y2)=0... (1)
now the points are A(1,5) B(K,1) and C(4,11) i.e.
x1=1 y1=5
x2=K y2=1
x3=4 y3=11
put these values in equation 1..
1(1-11) + K(11-5) + 4(5-1) =0
-10+ 6K +16 =0
6K+6=0.... 6K=-6
i.e. K=-1...
hope it helps you..
maths97:
can u plzz explain me the steps from starting
i have written it stepwise only
can u tell me that this question is from which Ch from class 10th R.S Agrwal book
hey i didn't remember the chapter name as i m not in 10th now
ok
thnx
ur wlcm
Thanks sis thank you sooooo much
ur welcome bro @abhiahlawat
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