Math, asked by rkdolic, 3 months ago

For what value k will the sum of roots of equation x^2-x=k(5x-1)is zero.Please solve itfast , don't post any irrelevant answer​ Chapter POLYNOMIAL

Answers

Answered by mathdude500
5

\large\underline{\sf{Solution-}}

Given quadratic equation is

\rm :\longmapsto\: {x}^{2} - x = k(5x - 1)

can be rewritten as

\rm :\longmapsto\: {x}^{2} - x = 5kx -k

\rm :\longmapsto\: {x}^{2} - x  - 5kx + k  = 0

\rm :\longmapsto\: {x}^{2} - x(1 + 5k) + k  = 0

We know that,

\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}

According to statement,

It is given that sum of the roots = 0

\rm :\longmapsto\:\dfrac{5k + 1}{1}  = 0

\rm :\longmapsto\:5k + 1 = 0

\rm :\longmapsto\:5k =  - 1

\bf\implies \:k =  -  \: \dfrac{1}{5}

Additional Information ;-

Nature of roots :-

Let us consider a quadratic equation ax² + bx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.

  • If Discriminant, D > 0, then roots of the equation are real and unequal.

  • If Discriminant, D = 0, then roots of the equation are real and equal.

  • If Discriminant, D < 0, then roots of the equation are unreal or complex or imaginary.

Where,

  • Discriminant, D = b² - 4ac
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