Question

for what value m, -5 is the zero of polynomial X square -x-(2m-2)​

Answer 1

Explanation:

$Given polynomial is x2−x(2k+2)</p><p></p><p>x2−2x(k+1)=0⟹x(x−2k+2)=0⟹x=0,2k+2</p><p></p><p>So the zeroes of polynomial are 0,2k+2</p><p></p><p>⟹k−2=0 or k−2=2k+2</p><p></p><p>⟹k=2 or k=−4</p><p></p><p>$

Given polynomial is x

2

−x(2k+2)

x

2

−2x(k+1)=0⟹x(x−2k+2)=0⟹x=0,2k+2

So the zeroes of polynomial are 0,2k+2

⟹k−2=0 or k−2=2k+2

⟹k=2 or k=−4

Answer 2

Answer:

5 + 10 +1 this is your answer