For what value n, the nth terms of AP's 59,61,63,...&-11,-4,3,10,...are equal
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use nth term of AP formula
tn=a+(n-1) d
where a is nth term of AP and d is common difference
for first series,
tn=59+(n-1)(2) --------(1)
for second series,
tn=-11+(n-1) 7 -------------(2)
a/c question
59+2 (n-1)=-11+7 (n-1)
70=5(n-1)
n=15
tn=a+(n-1) d
where a is nth term of AP and d is common difference
for first series,
tn=59+(n-1)(2) --------(1)
for second series,
tn=-11+(n-1) 7 -------------(2)
a/c question
59+2 (n-1)=-11+7 (n-1)
70=5(n-1)
n=15
mysticd:
Verify abhi , in first series , d= 8
now I think I'm right
U did a mistake again
In first ap d=61-59=2
yes I correct it
In second ap d= -4-(-11)=-4+11=7
yes I know
Is edit opiton is there
yes I edited
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