for what value of 1 is a zero of the polynomial x^2+x+k
Answers
Answered by
0
given
one of the polynomial is 1
polynomial =
x^2-x+k
(1)^2-(1)+k=0
1-1+k=0
=》 k=0
Answered by
0
Answer:
p(x)=x²+x+k
p(0)=0²+0+k
p(0)=0+0+k
p(0)=0
=0
p(x)=x²+x+k
p(1)=1²+1+k
p(1)=2²+k
=2²+k
p(x)=x²+x+k
p(2)=2²+2+k
p(2)=4²+k
=4²+k
no one should match this is wrong
hope it's help you
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