for what value of a,(3x-1) is a factor of the polynomial 6x^3+ax^2+x-2.
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Answer:
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Answer:
13
Step-by-step explanation:
Given
f(x)= 6x^3+ax^2+x-2
Let us assume
3x-1=0 ⇒3x=−1 ⇒x= 1/3
Since, (3x-1) is a factor of f(x) [Given]
∴ By factor theorem,
f( 1/3) =0
⇒6/27 + a/9 +1/3 -2 = 0
⇒3a= 39
⇒a= 13
Therefore, the value of a is 13
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