Math, asked by zfbrf, 25 days ago

for what value of a,(3x-1) is a factor of the polynomial 6x^3+ax^2+x-2.​

Answers

Answered by americanboyff
0

Answer:

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Answered by jm03041983
0

Answer:

13

Step-by-step explanation:

Given

f(x)= 6x^3+ax^2+x-2

Let us assume

3x-1=0 ⇒3x=−1 ⇒x= 1/3

Since, (3x-1) is a factor of f(x) [Given]

∴ By factor theorem,

f( 1/3) =0

⇒6/27 + a/9 +1/3 -2 = 0

⇒3a= 39

⇒a= 13

Therefore, the value of a is 13

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