Question

for what value of ‘a’ do the graph of function y=2ax + 1 and y=(a-6)x^2 – 2 do not intersect

Answer 1

Answer:

Step-by-step explanation:

The given equations are:

$y=2ax+1$ and $y=(a-60)x^{2}-2$

Since,the two equations do not intersect, therefore,

$2ax+1{\neq}(a-6)x^{2}-2$

$(a-6)x^{2}-2ax-3{\neq}0$

Now, Discriminant should be less than zero,

$b^{2}-4ac<0$

$4a^{2}-4(a-6)(-3)<0$

$a^{2}+3a-18<0$

$a^{2}+6a-3a-18<0$

$a(a+6)-3(a+6)<0$

$(a-3)(a+6)<0$

Therefore, a∈(-6,3).