for what value of a is the equation (x-5)^2=(x+5)^2-ax an identity.
Answers
Answered by
0
Answer:
2(x+1)
2x+2
2
=2x+2
=2x+2
=2.
Answered by
1
Answer:
(x-5)^2=(x+5)^2-ax
ax=(x+5)^2-(x-5)^2
=x^2+25+10x-x^2-25+10x
=20x
a=20
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