Question

for what value of a is (x-5) a factor of x^3-3x^2+ax-10?​

Answer 1

q(x)=x-5=0

x=5

since p(x) has a factor so p(x)=0

x^3-3x^2+ax-10=0

(5)^3-3(5)^2+a(5)-10=0

125-75+5a-10=0

40+5a=0

5a=-40

a= -8....

Step-by-step explanation:

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