for what value of a is (x-5)a factor of x³-3x²+ax-10
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Answered by
2
Step-by-step explanation:
q(x)=x-5=0
x=5
since p(x) has a factor so p(x)=0
x^3-3x^2+ax-10=0
(5)^3-3(5)^2+a(5)-10=0
125-75+5a-10=0
40+5a=0
5a=-40
a=-8
Answered by
0
Answer:
therefore a= -8
Step-by-step explanation:
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