Math, asked by parthlambore, 6 months ago

For what value of ‘a’ quadratic equation ax

2

 6x + 1 = 0 has no real roots ?

Answers

Answered by kayamramya2005

1

Step-by-step explanation:

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Answered by kumarghoshabhijit

0

Answer:

3ax2 - 6x + 1 = 0 (- 6)2 - 4(3a) (1) < 0 12a > 36 => a > 3

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