Physics, asked by jassmeet6284, 1 year ago

For what value of a the equation (a^2-a-2)x^2+(a^2-4x)x(a^2-3a+2)=0

Answers

Answered by subhalaxmisenapati19
0

Answer:

Given quadratic equation

(a

2

−a−2)x

2

+(a

2

−4)x+a

2

−3a+2=0

We know that Ax

2

+Bx+C=0 will have more than two solution, if

A=B=C=0

So, a

2

−a−2=0

⇒a=2,−1

a

2

−4=0

⇒a=−2,2

a

2

−3a+2=0

⇒(a−1)(a−2)=0

⇒a=1,2

Common value of a=2.

Explanation:

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