For what value of a the equation (a^2-a-2)x^2+(a^2-4x)x(a^2-3a+2)=0
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Answer:
Given quadratic equation
(a
2
−a−2)x
2
+(a
2
−4)x+a
2
−3a+2=0
We know that Ax
2
+Bx+C=0 will have more than two solution, if
A=B=C=0
So, a
2
−a−2=0
⇒a=2,−1
a
2
−4=0
⇒a=−2,2
a
2
−3a+2=0
⇒(a−1)(a−2)=0
⇒a=1,2
Common value of a=2.
Explanation:
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