Question

for what value of a, the pair of equations, 3x+2y-4=0 and ax-y-3=0 has a unique solution​

Answer 1

Answer:

value of 'a' can be anything except (-3/2) for having unique solution.

Step-by-step explanation:

given pair of equations are:

3x+2y-4=0 and ax-y-3=0

let us compare the above equations with kx + ly + m =0 and

                                                                     px + qy + n =0

so k = 3; l = 2 ; m = -4 and

p = a; q = -1 ; n = - 3

for having a unique solution (k/p) ≠ ((l/q)

⇒ (3/a) ≠ (2/ -1)

⇒ a  ≠ (-3/2)