Question

for what value of "a" the quadratic equation ax^2+2x+1=0 have real roots​

Answer 1

Answer:

A quadratic equation has two real roots if discriminant = 0

Step-by-step explanation:

For the given equation, we have: d = b2 – 4 a c d = (2)2 – 4 (1) (a2 + 1) d = 4 – 4(a2 + 1) d = 4(1 – a2 – 1) d = – 4a2 Now, D = 0 when a = 0.

So, the equation will have real and equal roots if a = 0. And for all other values of a, the equation will have no real roots.

No, there is no real value of ‘a’ for which the given equation has real roots.

Answer 2

Answer:

Value of "a" the quadratic equation ax²+2x+1=0 have real roots​ is 1

Step-by-step explanation:

∴ ax² + 2x + 1 = 0

Comparing the given equation with ax² + bx + c = 0

∴ a = a, b = 2, c = 1

∴b²-4ac = 0         (Given)

∴ 2² - 4 * a * 1 = 0

∴ 4 - 4a = 0

∴ 4 = 4a

∴ a = 4/4

∴ a =1