for what value of 'a' will be the expression 3x232x+a is divisible byx-2
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Answer:
p=2 and q=1
Step-by-step explanation:
Let f(x)=px
3
+x
2
−2x−q
Since f(x) is divisible by (x−1) and (x+1) so x=1 and −1 must make f(x)=0.
Therefore, p+1−2−q=0, i.e., p−q=1; and
−p+1+2−q=0, i.e., p+q=3
Thus p=2 and q=1
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