Question

For what value of a will (x + 3) be a factor of the polynomial x((x + 1)^2 + 8x} + ax (x+1)? please give fast

Answer 1

Step-by-step explanation:

p(x) = {(x + 1)²+ 8x} + ax (x+1)

(x + 3) is the factor of p(x)

x + 3 = 0

x = -3

p(-3) = (-3+1)²+8(-3)+a(-3)(-3+1) =0

= (-2)²-24-3a(-2) = 0

= 4-24+6a = 0

= -20+6a = 0

= a = -20/6

= -10/3

hope it is helpful to you