Question

For what value of & will the following
system of equations have no solutions ?
(2p-1)x+(p-1)y-2p+1; y+3x-1=0​

Answer 1

Answer:

0.4

Step-by-step explanation:

for no solution

a₁/a₂=b₁/b₂≠c₁/c₂

therefore a₁/a₂=b₁/b₂

2p-1/p-1 =1/3

6p-3 = p-1  

5p = 2

p = 2/5

p = 0.4 ans

a₁/a₂≠c₁/c₂

2p-1/p-1≠(-2p+1)/-1

2p-1/p-1≠ 2p-1

2p-1≠2p²-3p+1....................... do not cut 2p-1 from both side

2p²-5p+2≠0

2p²-4p-p+2≠0

2p(p-2) -1(p-2)≠0

(p-2)(2p-1)≠0

p≠2,1/2