For what value of angle x does sin x = 4/3 exist ?
Answers
sinx = 4/3 = 1.333.. > 1
but we know that maximum value of sine is 1 so, sinx ≠ 4/3 it's not possible .
actually , sinx = p/h { p =>perpendicular , h => hypotenuse }
we know, h >P for all real value of P and h
so, P/h < 1
hence, sinx ≠ greater then 1
Answer:
=> {cosθ(1 + sinθ) + cosθ(1 - sinθ)}/(1 - sinθ)(1 + sinθ) = 4
=> {cosθ + cosθ.sinθ + cosθ - cosθ.sinθ}/(1 - sin²θ) = 4
=> 2cosθ/cos²θ = 4 [ we know, sin²x + cos²x = 1 so, (1 - sin²θ) = cos²θ]
=> 2/cosθ = 4
=> cosθ = 1/2 = cos60°
hence, in 0 < θ < 90° , θ = 60°
now, if given equation is not defined.
(1 - sinθ) = 0
in 0 < θ < 90° , sinθ = 1 at 90°
hence, equation is undefined at θ = 90°
[ note : one more case for undefined, (1 + sinθ) = 0 , but in 0 < θ < 90° it's not possible. thars why I didn't mention it above]
Step-by-step explanation: