Question

for what value of are 2 p + 1, 13, 5 p- 3 three consecutive term of an ap?

Answer 1

#AlexaRousey here!!

If a1, a2 and a3 are in AP then,

=) a2 - a1 = a3 - a2 = d

Same here ;

=) 13 - (2p+1) = 5p-3 - 13

=) 13 - 2p-1 = 5p - 16

=) 12 - 2p = 5p - 16

=) 12+16 = 5p+2p

=) 28 = 7p

=) 28/7 = 4 = p

Hence numbers are 2(4) + 1, 13, 5(4)-3

= 9, 13, 17

Thanks!!

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\boxed{\red{\bold{Answer}}}$

$<b>$
a2-a1 = a3-a2
13-(2p+1)=5p-3-13
13-2p-1=5p-16
13+16-1=5p+2p
28=7p
p=28/7
p=4
$\huge\underline{\purple{\bold{Thanks}}}$