For what value of ‘b’ is (- 2) a zero of polynomial 3z2 + 4z + 2b
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Answer:
b = -2
Step-by-step explanation:
==: 3z² + 4z + 2b = 0 , at z = -2
==: 3*(-2)² + 4*(-2) + 2b = 0
==: 12 - 8 + 2b = 0
==: 4 + 2b = 0
==: 2b = -4
==: b = -2
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