Question

for what value of c are the factors of{x2-cx+81/16}

Answer 1

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Here is your answer
a = 1
b = c
c = 81/16
Now
$b {}^{2} - 4ac = 0 \\put \: the \: value \\ c {}^{2} - 4 \times 1 \times \frac{81}{16} = 0 \\ c {}^{2} = \frac{81}{4} \\ c = \sqrt{ \frac{81}{4} } \\ c = \frac{9}{2} \\ c = 4.5$

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Answer 2

Answer:

Here is answer for your question:

For equal roots

b2 - 4ac =0

Here b = - c and a = 1 , c = 81/16

Therefore,

b2 – 4ac =0

(-c)2 - 4(1)(81/16) = 0

c2 = 81/16

c = 9/4

Therefore factors are same for c = 9/4