for what value of c, the linear equation 2x-cy=8 has equal of x and y as it's solution
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According to the problem given,
2x + cy = 8 ------ ( 1 )
And
x = y -------------( 2 )
Put y = x in equation ( 1 ) we get ,
2x + cx = 8
Take x common
x ( 2 + c ) = 8
x = 8 / ( 2 + c )
But denominator should not be zero
2 + c not equals to zero
c is not equals to -2
and c = 0 , 2 and 6 satisfies the condition
2x + cy = 8
has equal values of x and y.
I hope this helps you.
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