for what value of h is the polynomial f(x)=
is exactly divisible by X + 2
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As ( x + 2 ) divides the given equation without leaving any remainder,
( x + 2 ) = 0
x = -2
Hence,
=> 2(-2)³ - h(-2)² + 5(-2) + 9 = 0
=> -16 - 4h - 10 + 9 = 0
=> -17 -4h = 0
=> -17/4 = h
( x + 2 ) = 0
x = -2
Hence,
=> 2(-2)³ - h(-2)² + 5(-2) + 9 = 0
=> -16 - 4h - 10 + 9 = 0
=> -17 -4h = 0
=> -17/4 = h
OmGitte:
I am also getting the same answer that is -17 by 4 but when we divide f of X by X + 2 then it is not coming zero
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