Question

For what value of k,

1
/4
is a root of the quadratic equation kx^2-x+
1/8= 0 ?​

Answer 1

Answer:

x=1/4

=kx²-x+1/8=0

k(1/4)²-(1/4)+1/8=0

1/16k-1/4+1/8=0

k-4+2. =0

16

k-2 =0

k=2

Answer 2

Step-by-step explanation:

GIVEN:-

1/4 is a root of the quadratic equation kx^2 -x+1/8.

TO FIND:-

The value of k.

UNDERSTANDING THE CONCEPT:-

According to your question,

1/2 is a root of quadratic equation.

So, It must satisfy the quadratic equation.

=> kx^2 - x + 1/8 = 0

REQUIRED ANSWER:-

$k( \dfrac{1}{4} ) {}^{2} - \dfrac{1}{4} + \dfrac{1}{8} = 0$

$\dfrac{k}{16} - \dfrac{1}{4} + \dfrac{1}{8} = 0$

LCM = 16

$\dfrac{k - 4 + 2}{16} = 0$

$k - 2 = 0$

=> k = 2

Therefore, Value of k is 2.