Question

For what value of k 16x2+4kx+9=0 has real and equal roots

Answer 1

Answer:

Your answer is 6. The explanation is in the attachment. Good luck

Step-by-step explanation:

Answer 2

Answer:

The value of k is 6,-6.

Step-by-step explanation:

Given : Equation $16x^2+4kx+9=0$

To find : For what value of k equation has real and equal roots ?

Solution :

Discriminant, $D=b^2-4ac$

Equal roots have discriminant zero,

$b^2-4ac=0$

On comparing $16x^2+4kx+9=0$ with $ax^2+bx+c=0$

a=16 , b=4k and c=9

Substitute the values,

$(4k)^2-4(16)(9)=0$

$16k^2-576=0$

$16k^2=576$

$k^2=\frac{576}{16}$

$k^2=36$

$k=\pm 6$

Therefore, The value of k is 6,-6.